Bellman-Ford algorithm is a single-source shortest path algorithm, so when you have negative edge weight then it can detect negative cycles in a graph. The only difference between the two …

1 Why does Bellman-Ford algorithm perform V-1 number of relaxation iterations? I feel that it is correct when going through examples. But how do we explain it for the general case? I have …

Mar 4, 2015 · 0 Bellman ford vs Dijkstra Bellman also work for negative weighted graph while Dijkstra work only for positive weighted graph. Bellman has TC O (V*E) which is greater than …

Feb 27, 2025 · The worst-case time complexity of Bellman-Ford algorithm is also O (V*E). This scenario occurs when the algorithm needs to iterate through all vertices and edges for |V| - 1 …

Jan 20, 2017 · Now coming to your original question, yes Bellman Ford algorithm can relax the edges in any arbitrary order as nicely answered by @ead above. But at the end of the final …

The Bellman-Ford algorithm determines the shortest path from a source $s$ to all other vertices. Initially the distance between $s$ and all other vertices is set to $\infty$.

Jun 9, 2020 · I am going thru Bellman-Ford. I have 2 doubts about the correctness of the algorithm: Why are we relaxing (num of vertices - 1) times all the edges? Why not some finite …

Apr 25, 2024 · The Bellman-Ford algorithm is capable of handling graphs with negative weights as long as there are no negative weight cycles reachable from the source vertex. Given the …

I have to find a negative cycle in a directed weighted graph. I know how the Bellman Ford algorithm works, and that it tells me if there is a reachable negative cycle. But it does not …

So in the Bellman-Ford algorithm we decide to update all nodes and their neighbors even though they might be visited before. My confusion can be summarized in a couple of questions: Why …